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Old 08-24-2010, 02:45 PM   #1
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New Dyno Numbers - 638 RWHP - 624 RWTQ ( what the HP at the block )

2010 camaro LS3 motor-Ran a test on a new mustang DYNO today. car hit 638 rwhp and 624 rwtq. many people have made comments that the mustang numbers are more true but are about 8 to 12 percent below and dynojet, in addition the flywheel horsepower would be even 12 to 15 percent more. At my present numbers at the rear wheel would this mean my motor is pushing 775HP at the flywheel, does this sound right???
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Old 08-24-2010, 03:10 PM   #2
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Using a 15% loss, it would be closer to 750 ...
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Old 08-24-2010, 03:13 PM   #3
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Quote:
Originally Posted by advfire View Post
2010 camaro LS3 motor-Ran a test on a new mustang DYNO today. car hit 638 rwhp and 624 rwtq. many people have made comments that the mustang numbers are more true but are about 8 to 12 percent below and dynojet, in addition the flywheel horsepower would be even 12 to 15 percent more. At my present numbers at the rear wheel would this mean my motor is pushing 775HP at the flywheel, does this sound right???
What is your Set up?
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Old 08-24-2010, 03:41 PM   #4
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Easy way to figure your wheel hp to engine hp is to divide by .85... or .8 for an auto.
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Old 08-24-2010, 03:58 PM   #5
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Easy way to figure your wheel hp to engine hp is to divide by .85... or .8 for an auto.
Or if you want to go from rwhp to flywheel... multiply by 1.15 or 1.2 for an auto!

math is fun!
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Old 08-24-2010, 04:05 PM   #6
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Or if you want to go from rwhp to flywheel... multiply by 1.15 or 1.2 for an auto!

math is fun!
not too fun as that doesn't work out ...


ex.

650 / .85 = 764.7
650 * 1.15 = 747.5


I think the / .85 way is correct ..

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Old 08-24-2010, 04:07 PM   #7
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maggie with 10 lbs bost
stage 2 cam
CAI
kooks 3' full headers to tip
meth injection
160deg ther


question is if you all think 750 would be a valid number using a mustang what do you think i would get using a dynojet?
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Old 08-24-2010, 04:08 PM   #8
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Multypling by 1.15 is more reasonable.

If a typical stock ls3 is 370...multiply that by 1.15 and you get 425.5
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Old 08-24-2010, 04:12 PM   #9
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Originally Posted by Crowley View Post
not too fun as that doesn't work out ...


ex.

650 / .85 = 764.7
650 * 1.15 = 747.5


I think the / .85 way is correct ..

Crowley
brb... doing this on pen and paper! lol


So the formula would be: x(1-y) = z

x = flywheel
y = % (15 for manual and 20 for auto)
z = rwhp

going from rwhp to flywheel would be: z/(1-y) = x
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Old 08-24-2010, 04:15 PM   #10
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Originally Posted by advfire View Post
maggie with 10 lbs bost
stage 2 cam
CAI
kooks 3' full headers to tip
meth injection
160deg ther


question is if you all think 750 would be a valid number using a mustang what do you think i would get using a dynojet?

it depends on how the dyno was set up ...

Just say the mustang dyno reads say 3 % lower than a dynojet ..

638 / .82 = 778

On a dynojet it could read 661 rwhp (778 / .85)

Again .. all depends on how the dynos are setup etc .. use the dyno as more of a tool for mods and see differences ...


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Old 08-24-2010, 04:16 PM   #11
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manual,

i guess the real question is if im getting 638 on a mustang what would i get on a dynojet and then what would be my end horsepower
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Old 08-24-2010, 04:18 PM   #12
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manual,

i guess the real question is if im getting 638 on a mustang what would i get on a dynojet and then what would be my end horsepower
reason being is that the orignal horsepower rating from chevy was posted on a dynojet, using the same type of gauge would be what i would compare with...
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Old 08-24-2010, 04:38 PM   #13
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manual,

i guess the real question is if im getting 638 on a mustang what would i get on a dynojet and then what would be my end horsepower
I'm not sure what you mean by end horsepower ... in the post just above this one I have an example (say if there is a 3% difference between a mustang and dynojet numbers). Your Engine HP is constant and will be the same on both, but your rear wheel HP will be different because one will read say 15% loss and the other maybe 18% loss ..

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Old 08-24-2010, 07:20 PM   #14
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I'm not sure what you mean by end horsepower ... in the post just above this one I have an example (say if there is a 3% difference between a mustang and dynojet numbers). Your Engine HP is constant and will be the same on both, but your rear wheel HP will be different because one will read say 15% loss and the other maybe 18% loss ..

Crowley
i guess it was my understanding that a mustang was about a 8% difference then a dyno and then 12% to 15% loss to the wheel. this is what i was interested in knowing
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