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Old 09-16-2021, 06:58 AM   #1
SoChrisB
 
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Whipple question.

So, I made the move to a 416 stroker and obviously lost some boost. I heard you can't overspin the whipple to more than 18k rpm. I currently have a 3.5 upper and a 6% OD lower. Any idea how low of a pulley I can go?

Appreciate the help all.
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Old 09-18-2021, 12:14 PM   #2
Brad7294
 
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I had the same question on here. I have stock block with Whipple on 11 lbs boost it's at 750 rwhp. I was going with 416 and either the 3.25 or 3.0 pulley and 6%od lower 10 rib. I was curious on the boost numbers. 17,18 psi?
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Old 09-27-2021, 11:31 AM   #3
Batmanntexas

 
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Quote:
Originally Posted by SoChrisB View Post
So, I made the move to a 416 stroker and obviously lost some boost. I heard you can't overspin the whipple to more than 18k rpm. I currently have a 3.5 upper and a 6% OD lower. Any idea how low of a pulley I can go?

Appreciate the help all.
Assuming Google is correct about the diameter of a stock Camaro LS3/L99 harmonic damper (7.75"), then below is the way to figure out your max pulley size:

(stock diameter * OD%) / (SC pulley size) = blower speed/engine speed ratio

blower/engine ratio * engine RPM = Blower speed

Example: (7.75 x 1.06) / 3.5 = 2.35 (rounded)
2.35 x 6000rpm = 14,100 blower RPM, at 7000rpm = 16,450 blower RPM

To get an accurate answer, you need to pick a MAX engine RPM and then calculate from there.

Quote:
Originally Posted by Brad7294 View Post
I had the same question on here. I have stock block with Whipple on 11 lbs boost it's at 750 rwhp. I was going with 416 and either the 3.25 or 3.0 pulley and 6%od lower 10 rib. I was curious on the boost numbers. 17,18 psi?
Your boost number is actually a resistance to airflow and not tied directly to blower RPM. If you dropped your current combination onto a 416 motor, your boost number would probably drop 3-4psi just from the additional cubic inches, even though the blower is still spinning the same speed. Additionally, Whipple claims about 1psi for each 1/8" decrease in pulley diameter (blower pulley).

-Scott
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Old 09-29-2021, 05:49 AM   #4
SoChrisB
 
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Quote:
Originally Posted by Batmanntexas View Post
Assuming Google is correct about the diameter of a stock Camaro LS3/L99 harmonic damper (7.75"), then below is the way to figure out your max pulley size:

(stock diameter * OD%) / (SC pulley size) = blower speed/engine speed ratio

blower/engine ratio * engine RPM = Blower speed

Example: (7.75 x 1.06) / 3.5 = 2.35 (rounded)
2.35 x 6000rpm = 14,100 blower RPM, at 7000rpm = 16,450 blower RPM

To get an accurate answer, you need to pick a MAX engine RPM and then calculate from there.



Your boost number is actually a resistance to airflow and not tied directly to blower RPM. If you dropped your current combination onto a 416 motor, your boost number would probably drop 3-4psi just from the additional cubic inches, even though the blower is still spinning the same speed. Additionally, Whipple claims about 1psi for each 1/8" decrease in pulley diameter (blower pulley).

-Scott
Thanks, Scott. I did the math already. I guess I'm wondering if anyone is overspinning the Whipple.
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Old 10-01-2021, 08:07 AM   #5
Batmanntexas

 
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I'm not overspinning it, but am close, at 17,600rpm @ 6500...

10%OD with 3" upper....

-Scott
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