Dilution HELP! - Camaro5 Chevy Camaro Forum / Camaro ZL1, SS and V6 Forums

AmericanMuscleCars · 06-26-2013, 04:17 PM

hey guys I have a 32 OZ bottle and I need to dilute a product 10:1 so 10 parts water to 1 part solution in a 32 OZ bottle. How many OZ do I need to fill up with solution and the rest with water? Thanks in advance!

Tecca · 06-26-2013, 04:25 PM

My god man how many places are you going to post this. LOL

Rounding everything out for a 10:1 solution go 3 oz of APC to 29 oz of water.

AmericanMuscleCars · 06-26-2013, 04:27 PM

Quote:

Originally Posted by Tecca

My god man how many places are you going to post this. LOL

Rounding everything out for a 10:1 solution go 3 oz of APC to 29 oz of water.

Can I do 2.5 OZ and fill the rest up to the 25 OZ line

lscamaro · 06-26-2013, 04:34 PM

Quote:

Originally Posted by Tecca

My god man how many places are you going to post this. LOL

Rounding everything out for a 10:1 solution go 3 oz of APC to 29 oz of water.

I didn't know doing simple math would be that difficult

ihaveacamaro · 06-26-2013, 04:37 PM

well, considering how both of you are doing simple math wrong...

AmericanMuscleCars · 06-26-2013, 04:37 PM

Quote:

Originally Posted by ihaveacamaro

well, considering how both of you are doing simple math wrong...

So what do I have to do lol? Is the 2.5 good enough?

ihaveacamaro · 06-26-2013, 04:40 PM

Quote:

Originally Posted by AmericanMuscleCars

So what do I have to do lol? Is the 2.5 good enough?

just do what tecca said, 3 oz APC to 29 oz water is fine. If you want to be real technical, 3 oz APC to 30 oz water is the proper dilution, but you won't see any difference with an extra ounce of water. Also 33 oz won't fit in a 32 oz bottle which is why I'm assuming Tecca said 3 to 29.

I was just making a joke since 1 x 3 = 3, but 10 x 3 doesn't equal 29

Tecca · 06-26-2013, 04:44 PM

Well lets get technical then

The Formula:
x / y = z

Where x = Total amount of product, in ounces, desired in the end.

Where y = Total number of parts for dilution. In a 10:1 dilution, this would be? 11.

Where z = Amount of liquid, in ounces, required per part.

So lets take the first one with 32oz at 10:1

32/11 = 2.9 That is where you come up with 3 because who is going to measure out 2.0oz.

Tecca · 06-26-2013, 04:46 PM

Quote:

Originally Posted by AmericanMuscleCars

So what do I have to do lol? Is the 2.5 good enough?

2.5 oz's in with 25 ounces is fine, if you put a little less or more it isn't going to matter.

ihaveacamaro · 06-26-2013, 04:48 PM

Quote:

Originally Posted by Tecca

In a 10:1 dilution, this would be? 10.

11 not 10.

in a 1/10 dilution, total parts equals 10.

Having the colon means parts of one ingredient to parts of other ingredient, not parts of one ingredient to parts of entire mix.

Again, I was just making a joke, it's really not a huge deal and makes no difference in this situation for the op.

AmericanMuscleCars · 06-26-2013, 04:48 PM

Quote:

Originally Posted by Tecca

2.5 oz's in with 25 ounces is fine, if you put a little less or more it isn't going to matter.

Thanks!

Tecca · 06-26-2013, 04:51 PM

Quote:

Originally Posted by ihaveacamaro

11 not 10.

in a 1/10 dilution, total parts equals 10.

Having the colon means parts of one ingredient to parts of other ingredient, not parts of one ingredient to parts of entire mix.

Again, I was just making a joke, it's really not a huge deal and makes no difference in this situation for the op.

It's all good but always I always went by

For every dilution there are a total number of "parts".
Let's say that you want a 5:1 dilution - that means there are 6 parts (the 5 parts and the 1 part = 6 parts). 10:1 = 11 parts. Etc.

Quote:

Again, I was just making a joke, it's really not a huge deal and makes no difference in this situation for the op

ihaveacamaro · 06-26-2013, 04:55 PM

Quote:

Originally Posted by Tecca

Where y = Total number of parts for dilution. In a 10:1 dilution, this would be? 10.

Quote:

Originally Posted by Tecca

10:1 = 11 parts. Etc.

I agree entirely with your second quote, but not your first.

Tecca · 06-26-2013, 04:59 PM

Quote:

Originally Posted by ihaveacamaro

I agree entirely with your second quote, but not your first.

LOL

Fixed

06-26-2013, 04:17 PM	#1
AmericanMuscleCars Teenage Dream Camaro Drives: A Visually Stunning Camaro Join Date: Feb 2013 Location: Florida Posts: 1,722	Dilution HELP! hey guys I have a 32 OZ bottle and I need to dilute a product 10:1 so 10 parts water to 1 part solution in a 32 OZ bottle. How many OZ do I need to fill up with solution and the rest with water? Thanks in advance!

06-26-2013, 04:37 PM	#5
ihaveacamaro I like teeth. Drives: #198 Join Date: Oct 2009 Location: Ft. Lauderdale, Florida Posts: 4,817	well, considering how both of you are doing simple math wrong... __________________ . Please check out my youtube detailing channel: http://www.youtube.com/user/roshan517 "When you want to succeed as bad as you want to breathe, then you will be successful."

06-26-2013, 04:44 PM	#8
Tecca . Drives: ... Join Date: Apr 2009 Location: Colorado Posts: 1,377	Well lets get technical then The Formula: x / y = z Where x = Total amount of product, in ounces, desired in the end. Where y = Total number of parts for dilution. In a 10:1 dilution, this would be? 11. Where z = Amount of liquid, in ounces, required per part. So lets take the first one with 32oz at 10:1 32/11 = 2.9 That is where you come up with 3 because who is going to measure out 2.0oz. Last edited by Tecca; 06-26-2013 at 04:58 PM. Reason: Dumb mistake

06-26-2013, 04:25 PM	#2
Tecca . Drives: ... Join Date: Apr 2009 Location: Colorado Posts: 1,377	My god man how many places are you going to post this. LOL Rounding everything out for a 10:1 solution go 3 oz of APC to 29 oz of water.